LeetCode 솔루션

[8/30] 48. Rotate Image

학부유학생 쪽지보내기 메일보내기 자기소개 아이디로 검색 전체게시물 작성
작성일 2022.08.29 17:49

3,398 조회
1 댓글
0 추천
0 비추천
목록 게시글 쓰기

Medium

11082548Add to ListShare

You are given an n x n 2D matrix representing an image, rotate the image by 90 degrees (clockwise).

You have to rotate the image in-place, which means you have to modify the input 2D matrix directly. DO NOT allocate another 2D matrix and do the rotation.

Example 1:

Input: matrix = [[1,2,3],[4,5,6],[7,8,9]]
Output: [[7,4,1],[8,5,2],[9,6,3]]

Example 2:

Input: matrix = [[5,1,9,11],[2,4,8,10],[13,3,6,7],[15,14,12,16]]
Output: [[15,13,2,5],[14,3,4,1],[12,6,8,9],[16,7,10,11]]

Constraints:

n == matrix.length == matrix[i].length
1 <= n <= 20
-1000 <= matrix[i][j] <= 1000

Accepted

1,015,099

Submissions

1,482,894

#Cisco, #Apple, #Microsoft, #Adobe, #Amazon, #Facebook, #Google, #Uber, #Epam Systems, #Bloomberg, #Oracle, #Paypal, #Tiger Analytics, #Yahoo

링크

https://leetcode.com/problems/rotate-image/ 1734 회 연결

익명
작성일 2022.08.29 17:50

Runtime: 38 ms, faster than 91.36% of Python3 online submissions for Rotate Image.
Memory Usage: 13.8 MB, less than 74.32% of Python3 online submissions for Rotate Image.

class Solution:
    def rotate(self, matrix: List[List[int]]) -> None:
        """
        Do not return anything, modify matrix in-place instead.
        """
        top, bottom = 0, len(matrix)-1
        left, right = 0, len(matrix[0])-1
        
        while left < right or top < bottom:
            for i in range(right - left):
                # tl->tr
                temp_rt = matrix[top+i][right]
                matrix[top+i][right] = matrix[top][left+i]
                
                # rt->rb
                temp_rb = matrix[bottom][right-i]
                matrix[bottom][right-i] = temp_rt
                
                #rb->lb
                temp_lb = matrix[bottom-i][left]
                matrix[bottom-i][left] = temp_rb
                
                #lb->tl
                matrix[top][left+i] = temp_lb
            
            left +=1
            right -=1
            top+=1
            bottom-=1
        
        return matrix

Runtime: 38 ms, faster than 91.36% of Python3 online submissions for Rotate Image.
Memory Usage: 13.8 MB, less than 74.32% of Python3 online submissions for Rotate Image.
[code=Python 3]class Solution:
    def rotate(self, matrix: List[List[int]]) -> None:
        """
        Do not return anything, modify matrix in-place instead.
        """
        top, bottom = 0, len(matrix)-1
        left, right = 0, len(matrix[0])-1
        
        while left < right or top < bottom:
            for i in range(right - left):
                # tl->tr
                temp_rt = matrix[top+i][right]
                matrix[top+i][right] = matrix[top][left+i]
                
                # rt->rb
                temp_rb = matrix[bottom][right-i]
                matrix[bottom][right-i] = temp_rt
                
                #rb->lb
                temp_lb = matrix[bottom-i][left]
                matrix[bottom-i][left] = temp_rb
                
                #lb->tl
                matrix[top][left+i] = temp_lb
            
            left +=1
            right -=1
            top+=1
            bottom-=1
        
        return matrix
    
[/code]