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[10/31] 766. Toeplitz Matrix
본문
Easy
2982148Add to ListShareGiven an m x n
matrix
, return true
if the matrix is Toeplitz. Otherwise, return false
.
A matrix is Toeplitz if every diagonal from top-left to bottom-right has the same elements.
Example 1:
Input: matrix = [[1,2,3,4],[5,1,2,3],[9,5,1,2]] Output: true Explanation: In the above grid, the diagonals are: "[9]", "[5, 5]", "[1, 1, 1]", "[2, 2, 2]", "[3, 3]", "[4]". In each diagonal all elements are the same, so the answer is True.
Example 2:
Input: matrix = [[1,2],[2,2]] Output: false Explanation: The diagonal "[1, 2]" has different elements.
Constraints:
m == matrix.length
n == matrix[i].length
1 <= m, n <= 20
0 <= matrix[i][j] <= 99
Follow up:
- What if the
matrix
is stored on disk, and the memory is limited such that you can only load at most one row of the matrix into the memory at once? - What if the
matrix
is so large that you can only load up a partial row into the memory at once?
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class Solution:
def isToeplitzMatrix(self, matrix: List[List[int]]) -> bool:
ROW, COL = len(matrix), len(matrix[0])
for col in range(COL):
r, c = 0, col
num = matrix[r][c]
while r<ROW and c<COL:
if num != matrix[r][c]: return False
c += 1
r += 1
for row in range(ROW):
r, c = row, 0
num = matrix[r][c]
while r<ROW and c<COL:
if num != matrix[r][c]: return False
c += 1
r += 1
return True