LeetCode 솔루션

[11/21] 1926. Nearest Exit from Entrance in Maze

학부유학생 쪽지보내기 메일보내기 자기소개 아이디로 검색 전체게시물 작성
작성일 2022.11.21 12:59

5,772 조회
1 댓글
0 추천
0 비추천
목록

글검색

게시글 쓰기

1926. Nearest Exit from Entrance in Maze

Medium

152857Add to ListShare

You are given an m x n matrix maze (0-indexed) with empty cells (represented as '.') and walls (represented as '+'). You are also given the entrance of the maze, where entrance = [entrancerow, entrancecol] denotes the row and column of the cell you are initially standing at.

In one step, you can move one cell up, down, left, or right. You cannot step into a cell with a wall, and you cannot step outside the maze. Your goal is to find the nearest exit from the entrance. An exit is defined as an empty cell that is at the border of the maze. The entrance does not count as an exit.

Return the number of steps in the shortest path from the entrance to the nearest exit, or -1 if no such path exists.

Example 1:

Input: maze = [["+","+",".","+"],[".",".",".","+"],["+","+","+","."]], entrance = [1,2]
Output: 1
Explanation: There are 3 exits in this maze at [1,0], [0,2], and [2,3].
Initially, you are at the entrance cell [1,2].
- You can reach [1,0] by moving 2 steps left.
- You can reach [0,2] by moving 1 step up.
It is impossible to reach [2,3] from the entrance.
Thus, the nearest exit is [0,2], which is 1 step away.

Example 2:

Input: maze = [["+","+","+"],[".",".","."],["+","+","+"]], entrance = [1,0]
Output: 2
Explanation: There is 1 exit in this maze at [1,2].
[1,0] does not count as an exit since it is the entrance cell.
Initially, you are at the entrance cell [1,0].
- You can reach [1,2] by moving 2 steps right.
Thus, the nearest exit is [1,2], which is 2 steps away.

Example 3:

Input: maze = [[".","+"]], entrance = [0,0]
Output: -1
Explanation: There are no exits in this maze.

Constraints:

maze.length == m
maze[i].length == n
1 <= m, n <= 100
maze[i][j] is either '.' or '+'.
entrance.length == 2
0 <= entrancerow < m
0 <= entrancecol < n
entrance will always be an empty cell.

Accepted

63,725

Submissions

129,260

#Amazon

링크

https://leetcode.com/problems/nearest-exit-from-entrance-in-maze/ 1419 회 연결

익명
작성일 2022.11.21 13:00

from collections import deque
class Solution:
    def nearestExit(self, maze: List[List[str]], entrance: List[int]) -> int:
        ROW, COL = len(maze), len(maze[0])
        
        visited = set()
        visited.add((entrance[0],entrance[1]))
        
        queue = deque([(entrance[0], entrance[1], 0)])
        
        directions = [(1,0), (0,1), (-1,0),(0,-1)]
        
        while queue:
            r, c, steps = queue.popleft()
            
            if (r == 0 or r == ROW - 1 or c == 0 or c == COL -1) and (r,c) != (entrance[0],entrance[1]):
                return steps
            
            for rdir, cdir in directions:
                nr, nc = r+rdir, c+cdir
                if 0<=nr<ROW and 0<=nc<COL and (nr, nc) not in visited and maze[nr][nc] == ".":
                    queue.append((nr, nc, steps+1))
                    visited.add((nr, nc))
        
        return -1

Runtime: 1120 ms, faster than 77.13% of Python3 online submissions for Nearest Exit from Entrance in Maze.
Memory Usage: 15.6 MB, less than 27.25% of Python3 online submissions for Nearest Exit from Entrance in Maze.
[code=Python 3]from collections import deque
class Solution:
    def nearestExit(self, maze: List[List[str]], entrance: List[int]) -> int:
        ROW, COL = len(maze), len(maze[0])
        
        visited = set()
        visited.add((entrance[0],entrance[1]))
        
        queue = deque([(entrance[0], entrance[1], 0)])
        
        directions = [(1,0), (0,1), (-1,0),(0,-1)]
        
        while queue:
            r, c, steps = queue.popleft()
            
            if (r == 0 or r == ROW - 1 or c == 0 or c == COL -1) and (r,c) != (entrance[0],entrance[1]):
                return steps
            
            for rdir, cdir in directions:
                nr, nc = r+rdir, c+cdir
                if 0<=nr<ROW and 0<=nc<COL and (nr, nc) not in visited and maze[nr][nc] == ".":
                    queue.append((nr, nc, steps+1))
                    visited.add((nr, nc))
        
        return -1[/code]