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[11/28] 2225. Find Players With Zero or One Losses
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Medium
111081Add to ListShareYou are given an integer array matches
where matches[i] = [winneri, loseri]
indicates that the player winneri
defeated player loseri
in a match.
Return a list answer
of size 2
where:
answer[0]
is a list of all players that have not lost any matches.answer[1]
is a list of all players that have lost exactly one match.
The values in the two lists should be returned in increasing order.
Note:
- You should only consider the players that have played at least one match.
- The testcases will be generated such that no two matches will have the same outcome.
Example 1:
Input: matches = [[1,3],[2,3],[3,6],[5,6],[5,7],[4,5],[4,8],[4,9],[10,4],[10,9]] Output: [[1,2,10],[4,5,7,8]] Explanation: Players 1, 2, and 10 have not lost any matches. Players 4, 5, 7, and 8 each have lost one match. Players 3, 6, and 9 each have lost two matches. Thus, answer[0] = [1,2,10] and answer[1] = [4,5,7,8].
Example 2:
Input: matches = [[2,3],[1,3],[5,4],[6,4]] Output: [[1,2,5,6],[]] Explanation: Players 1, 2, 5, and 6 have not lost any matches. Players 3 and 4 each have lost two matches. Thus, answer[0] = [1,2,5,6] and answer[1] = [].
Constraints:
1 <= matches.length <= 105
matches[i].length == 2
1 <= winneri, loseri <= 105
winneri != loseri
- All
matches[i]
are unique.
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Submissions
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Runtime: 2493 ms, faster than 79.97% of Python3 online submissions for Find Players With Zero or One Losses.
Memory Usage: 70.4 MB, less than 10.26% of Python3 online submissions for Find Players With Zero or One Losses.
Memory Usage: 70.4 MB, less than 10.26% of Python3 online submissions for Find Players With Zero or One Losses.
from collections import defaultdict
class Solution:
def findWinners(self, matches: List[List[int]]) -> List[List[int]]:
players = set()
res = [[],[]]
lost = defaultdict(int)
for winner, loser in matches:
players.add(winner); players.add(loser);
lost[loser]+=1
for player in sorted(list(players)):
if player not in lost:
res[0].append(player)
elif lost[player] == 1:
res[1].append(player)
return res