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[12/15] 1143. Longest Common Subsequence

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본문

Given two strings text1 and text2, return the length of their longest common subsequenceIf there is no common subsequence, return 0.

subsequence of a string is a new string generated from the original string with some characters (can be none) deleted without changing the relative order of the remaining characters.

  • For example, "ace" is a subsequence of "abcde".

common subsequence of two strings is a subsequence that is common to both strings.

 

Example 1:

Input: text1 = "abcde", text2 = "ace" 
Output: 3  
Explanation: The longest common subsequence is "ace" and its length is 3.

Example 2:

Input: text1 = "abc", text2 = "abc"
Output: 3
Explanation: The longest common subsequence is "abc" and its length is 3.

Example 3:

Input: text1 = "abc", text2 = "def"
Output: 0
Explanation: There is no such common subsequence, so the result is 0.

 

Constraints:

  • 1 <= text1.length, text2.length <= 1000
  • text1 and text2 consist of only lowercase English characters.
Accepted
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class Solution:
    def longestCommonSubsequence(self, text1: str, text2: str) -> int:
    #     a f e
    #   0 0 0 0
    # a 0 1 1 1
    # b 0 1 1 1
    # c 0 1 1 1
    # a 0 1 1 1
    # e 0 1 1 2
        dp = [ [ 0 for _ in range(len(text1)+1) ] for _ in range(len(text2)+1) ]

        for i in range(len(text2)):
            for j in range(len(text1)):
                if text1[j] == text2[i]:
                    dp[i+1][j+1] = dp[i][j]+1
                else:
                    dp[i+1][j+1] = max(dp[i+1][j], dp[i][j+1])
        
        return dp[-1][-1]
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